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Period of f(x)= [sin3x]+|cos 6x| Please explain particularly about sin 3x period


2 years ago

Arun
25768 Points
							Dear Priya$f(x) = [sin(3x)] + |cos(6x)|$$f(x) = f_{1}(x) + f_{2}(x)$$f_{1}(x) = [sin(3x)]$$= 0, 0\leq x\leq \frac{\pi }{3}$$= -1, \frac{\pi }{3}\leq x\leq \frac{2\pi }{3}$Time period of f1(x):$\frac{2\pi }{3} = \frac{4\pi }{6}$$f_{2}(x) = |cos(6x)|$Time period of f2(x):$\frac{\pi }{6}$Time period of f(x):(LCM of time period of f1(x) & f2(x))/(HCFof time period of f1(x) & f2(x))$\frac{4\pi }{6} = \frac{2\pi }{3}$  In case of any difficulty, plese feel free to ask. RegardsArun

2 years ago
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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions