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Number of solutions of the equation tan x + sec x = 2 cos x, lying in the interval [0, 2p] is
tan x + sec x = 2cosxsin x + 1 = 2cos2xsin x + 1 = 2 (1 - sin2x)2 sin2x + sin x - 1 = 0Hence, we getsin x = - 1, or sin x = 1/2sin x = -1 orcosx = 0, which is not possible? sin x = 1/2x = p or x = p - (p / 6), in the interval [0, 2p]x = p or x = 5p / 6ThanksBharat BajajIIT Delhiaskiitians faculty
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