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`        Number of solution(s)of the equation  sin2A + cos2A = -1/2 ; A belongs in range[0,pi/2](a)0 (b)1(c)2(d)3please provide the step-wise solution`
one year ago

waqar malik
14 Points
```							squaring on both sides we get..1+2sin2Acos2A=1/4(since, 2sinAcosA=sin2A)therefore, 1+sin4A=1/4again,            sin4A=-3/4….….….(1)Since , A ~[0, pi/2]Therefore, 4A~[0, 2pi]from equation 1 it is clear that angle 4A will be in 3rd or 4th quadrant,Hence the equation has only 2 solutions.
```
18 days ago
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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions