Grade 11Trigonometry
ncert class 11 physics chapter 2 example 2.2 How to find value of tan 40?
ncert class 11 physics chapter 2 example 2.2
How to find value of tan 40?
1 Answer
Abdul Rahman
the best way is to use the Maclaurin series
tanx = x + 1x3/3 + 2x5/15 + 17x7/317 + 62x9/2835.....(x is angle in radians)
x = 40 degrees = 2/9pi = 0.7 radians
tan 40 = 0.7 + (0.7)3/3 + 2(0.7)5/15 + 17(0.7)7/317 +....
tan 40 = 0.7 + 0.11433 + 0.0.0224 + 0.004
tan 40 = 0.84 (approx.)
tanx = x + 1x3/3 + 2x5/15 + 17x7/317 + 62x9/2835.....(x is angle in radians)
x = 40 degrees = 2/9pi = 0.7 radians
tan 40 = 0.7 + (0.7)3/3 + 2(0.7)5/15 + 17(0.7)7/317 +....
tan 40 = 0.7 + 0.11433 + 0.0.0224 + 0.004
tan 40 = 0.84 (approx.)
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