Grade 6Trigonometry
Minimum value of 3cosx +4sin + 8 is A.5B.9C.7D.3
2 Answers
Abhiram
Minimum value of an equation of the form a cosx+b sinx+c is
Here,c=8 a=3 b=4
=> minimum value= 
=> minimum value= 8 - 5= 3
Therefore,the answer is (D)
Mosaraf Mondal
Min value=8- (3^2 + 4^2)^0.5 =8- (9 + 16 )^0.5 =8- 5 =3[ since minumume value of ax+by+c= c- (a^2 + b^2)^0.5]So exact ans is D.3
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