( m+2 )sinA + (2m – 1)cosA= ( 2m+1 )then find tanA.( I first divided the eq. by cosA and then squared it . then replacing sec2A with 1+tan2Athus forming a quadratic eq. in tanA but then the discriminant could not be factorised. the answer of this ques is purely a fraction independent of m. so please solve this ques for me)
( m+2 )sinA + (2m – 1)cosA
= ( 2m+1 )
then find tanA.
( I first divided the eq. by cosA and then squared it . then replacing sec2A with 1+tan2A
thus forming a quadratic eq. in tanA but then the discriminant could not be factorised. the answer of this ques is purely a fraction independent of m. so please solve this ques for me)