Let θ belong to (0,45), T 1 =Tan θ tanθ T 2 =Tan θ cot θ T 3= cot θ tan θ T 4 =Cot θ cotθ Arrange T 1 , T 2 , T 3 , T 4 in descending order.

Question

Let θ belong to (0,45), T 1 =Tan θ tanθ T 2 =Tan θ cot θ T 3= cot θ tan θ T 4 =Cot θ cotθ Arrange T 1 , T 2 , T 3 , T 4 in descending order.

Arun · Answer

Dear student in (0, 45) cot theta is always gretee than tan theta hence T4 will be the greatest Now T3 will come in larger hence in descending order T4 > T3 > T1 >T2

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Let θ belong to (0,45), T 1 =Tan θ tanθ T 2 =Tan θ cot θ T 3= cot θ tan θ T 4 =Cot θ cotθ Arrange T 1 , T 2 , T 3 , T 4 in descending order.

Let θ belong to (0,45),
T₁=Tan θ^tanθ
T₂=Tan θ ^cot θ
T₃₌cot θ^tan θ
T₄=Cot θ ^cotθ
Arrange T₁, T₂, T₃, T₄ in descending order.

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Let θ belong to (0,45), T 1 =Tan θ tanθ T 2 =Tan θ cot θ T 3= cot θ tan θ T 4 =Cot θ cotθ Arrange T 1 , T 2 , T 3 , T 4 in descending order.

Let θ belong to (0,45),T1=Tan θtanθ T2=Tan θ cot θT3=cot θtan θT4=Cot θ cotθArrange T1, T2, T3, T4 in descending order.

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Let θ belong to (0,45),
T₁=Tan θ^tanθ
T₂=Tan θ ^cot θ
T₃₌cot θ^tan θ
T₄=Cot θ ^cotθ
Arrange T₁, T₂, T₃, T₄ in descending order.