Flag Trigonometry> It's a question from resonance booklet......
question mark

It's a question from resonance booklet... Plz may I know the answer??

Kalika Singh , 6 Years ago
Grade 11
anser 1 Answers
Avinash

Last Activity: 6 Years ago

continuation for the above sum;-)=-Sin^2?cos^2?[cos^(n-4)?+sin^(n-4)?]=-sin^2?cos^2?[P(n-4)]2) Q(n-2) =cos^n?/cos^2?-sin^n?/sin^2?Q(n)-Q(n-2)=cos^n?[1-1/cos^2?]+sin^n?[1/sin^2?-1]==cos^n?[-sin^2?/cos^2?]+sin^n?[cos^?/sin^2?]=sin^2?cos^2?[-cos^(n-4)?+sin^(n-4)?]=-sin^2?cos^2?[Q(n-4)](3) P(4)=cos^4?+sin^4? =[cos^2?+sin^2?]^2-2sin^2?cos^2? ==1-2sin^2?cos^2?(4). Q(4)=cos^4?-sin^4? =[Cos^2?+sin^2?].[cos^2?-sin^2?] =cos^2?-sin^2?..
P(n-2)=cos^(n-2)?+sin^(n-2)? =cos^(n)?/cos^2?+sin^(n)?/sin^2?P(n)-P(n-2)=cos^n?[1-1/cos^2?]+sin^n?[1-1/sin^2?]==Cos^n?[-sin^2?/cos^2?]+sin^n?[-cos^2?/sin^2?]==Sin^2?.cos^2?[-cos^(n-4)?-sin^(n-4)?]==Sin^2?cos^2?

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...