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Grade: 11
        
It is a trigonometry related sum and you have to find the value of the given expression
10 months ago

Answers : (2)

Arun
20415 Points
							
sqrt (3)*csc20° - sec20° 
= sqrt (3)*(1/sin20°) - 1/cos20° 
= (sqrt (3)*cos20° - sin20°)/(sin20°*cos20°) 
= 4*[(sqrt (3)/2)*cos20° - (1/2) sin20°]/(2sin20°cos20°) 
= 4*(cos30°cos20° - sin30°sin20°)/sin (2*20°) 
= 4*cos (30°+20°)/sin40° 
= 4*cos50°/sin (90°-50°) 
= 4*cos50°/cos50° 
= 4.
10 months ago
Soumendu Majumdar
159 Points
							
Dear Student,
Though I know that your question is wrong as per your class since you have posted it I’ll find the value of the expression and you should also know the question should be \sqrt3 cosec20^{\circ}-sec20^{\circ}
Now to find the value of the expression you have posted we need to know the values of cosec20^{\circ} & sec20^{\circ}
cosec20^{\circ} =2.92380440294(You can use an approximated value)
sec20^{\circ} =1.06417777336(You can use an approximated value)
so,
cosec^220^{\circ} =8.54863218665
sec^220^{\circ} =1.13247433331
so the value of \sqrt3 cosec20^{\circ}-sec20^{\circ}=13.6741909491 (Take approximate value)
Now to find the value of the correct expression,
First, multiply with ½ to both numerator & denominator
so we get
\sqrt3(0.5)cosec20^{\circ}-0.5sec20^\circ
4(cos30^{\circ}cos20{^\circ}-sin30^{\circ}sin20{^\circ})/(2sin20{^\circ}cos20{^\circ})
=4 cos(30+20)^\circ /sin(40)^\circ
=4 cos50^\circ/sin(90-50)^\circ
=4 cos50^\circ/cos(50)^\circ
=4
Hope it helps!
10 months ago
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