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Grade: 12th pass
        
  1. Integral-pi to pi cos2xcos3x by using exponential form
one year ago

Answers : (1)

Aditya Gupta
1819 Points
							
we know that cosx=(e^ix+e^-ix)/2
so cos2xcos3xdx =(ei2x + e-i2x)(ei3x + e-i3x)dx/4
= (ei5x + 2e-ix + e-i5x)dx/4
now simply integrate these exponential functions.
1/4*(e^i5x/5i + 2e^-ix/-i +e-i5x/-5i)
and substitute the limits to get the final answer as zero
one year ago
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