In triangle ABC, D is the mid point of BC. If AD is the perpendicular to AC, then cosAcosC= ?[1]2(c2+a2) / 3ac[2](c2-a2) / 3ac[3]3(c2+a2) /3ac[4]2(c2-a2) /3ac

Shubhashish singh , 9 Years ago

Grade 11