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In triangle ABC angle C = 90 degrees Prove That, [(1 - sin A)/(1 + cos B)]^1/2 = secA - cot B

In triangle ABC angle C = 90 degrees 

Prove That,

[(1 - sin A)/(1 + cos B)]^1/2 = secA - cot B

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Grade:9

1 Answers

Harsh Patodia IIT Roorkee
askIITians Faculty 907 Points
6 years ago
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