In triangle ABC angle C = 90 degrees
Prove That,
[(1 - sin A)/(1 + cos B)]^1/2 = secA - cot B
In triangle ABC angle C = 90 degrees
Prove That,
[(1 - sin A)/(1 + cos B)]^1/2 = secA - cot B
Priya , 7 Years ago
Grade 9
Trigonometry> In triangle ABC angle C = 90 degrees Prov...
1 Answers
Harsh Patodia
Last Activity: 7 Years ago
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