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In the expression (x tan α + y cot α) (x cot α +y tan α) - 4xy cot 2 2α is????? Pls send a detailed solution.....
P= (x tan α + y cot α) (x cot α +y tan α) - 4xy cot2 2α = x^2+y^2+xy(tan^2α+cot^2α – 4cot2 2α)now, we use the following identity: cotz-tanz=2cot2zso, we have P= x^2+y^2+xy(tan^2α+cot^2α – (cotα – tanα)^2)=x^2+y^2+xy(2) = (x+y)^2
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