Arun
Last Activity: 6 Years ago
Given in the question;
Cotangent (Cot)ABD = 1.5
can be written as Cot ABD = AB/AD => 3/2
[Cot = Perpendicular/Base] => AB = 3x, AD = 2x => By Pythagoras theorem in right angled triangle ABD AB2 + AD2 = BD2(3x)^2 + (2x)^2 = (26)^29x^2 + 4x^2 = 676x^2 = 676/13x^2 = 52x = 2 sqrt13 cm
Thus, AB = 3x => 3 × 2 sqrt13
AB = 6 sqrt13
AD = 2x => 2 × 2 sqrt13
AD = 4 sqrt13
Now Area of rectangle ABCD = AB × AD (length × breadth)
i.e. 6 sqrt13 × 4 sqrt13
=> 24 × 13
=> 312 cm^2
And Perimeter of the rectangle = 2 (AB + AD) [2(length + breadth)]
=> 2 (6 sqrt13 + 4 sqrt13)
=> 2 × 10 sqrt13
=> 20 sqrt13 cm
