MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        
in any triangle, show that sin(A + B + C) = sinAcosBcosC + sinBcosAcosC + sinCcosAcosB, where A, B, C : are angles.
2 years ago

Answers : (1)

Arun
23041 Points
							
Dear Student
 
  Use the formula 
sin(a + b) = sina cosb + sinb cos a 

Then sin(a + b + c) 
= sin((a + b) + c) 
= sin(a + b) cosc + cos(a + b) sin c 

Then use the formula 
cos(a + b) = cosa cosb - sina sinb to get 

sin(a + b) cosc + cos(a + b) sin c 
= (sina cosb + sinb cosa) cosc + (cosa cosb - sina sinb) sinc 
= sina cosb cosc + sinb cosa cosc + sinc cosa cosb - sina sinb sinc
 
Regards
Arun (askIITians forum expert)
2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 31 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details