In any triangle, if

a square-b square divided by a square+b square=sin(A-B) divided by sin(A+B), then prove that the triangle is either right angled or isoceles.

Question

In any triangle, if a square-b square divided by a square+b square=sin(A-B) divided by sin(A+B), then prove that the triangle is either right angled or isoceles.

MuraliKrishna Medavaram · Answer

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In any triangle, if a square-b square divided by a square+b square=sin(A-B) divided by sin(A+B), then prove that the triangle is either right angled or isoceles.

In any triangle, if

a square-b square divided by a square+b square=sin(A-B) divided by sin(A+B), then prove that the triangle is either right angled or isoceles.

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In any triangle, if a square-b square divided by a square+b square=sin(A-B) divided by sin(A+B), then prove that the triangle is either right angled or isoceles.

In any triangle, ifa square-b square divided by a square+b square=sin(A-B) divided by sin(A+B), then prove that the triangle is either right angled or isoceles.

1 Answers

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In any triangle, if

a square-b square divided by a square+b square=sin(A-B) divided by sin(A+B), then prove that the triangle is either right angled or isoceles.