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IN AN ACUTE ANGLE TRIANGLE ABC , sec A( 1+ sec A) secB(1+secB) sec C (1+sec C ) =? IN AN ACUTE ANGLE TRIANGLE ABC , sec A( 1+ sec A) secB(1+secB) sec C (1+sec C ) =?
Dear studentAs there is no condition consider equilateral triangleSec A = 2 = Sec B= Sec CAns is (2*3)*(2*3)*(2*3) = 216Regards
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