0

Guest

Courses New

IN AN ACUTE ANGLE TRIANGLE ABC , sec A( 1+ sec A) secB(1+secB) sec C (1+sec C ) =?

IN AN ACUTE ANGLE TRIANGLE ABC , sec A( 1+ sec A) secB(1+secB) sec C (1+sec C ) =?
 

Grade:12th pass

1 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
4 years ago
Dear student

As there is no condition consider equilateral triangle

Sec A = 2 = Sec B= Sec C

Ans is (2*3)*(2*3)*(2*3) = 216

Regards

Think You Can Provide A Better Answer ?

Other Related Questions on Trigonometry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More