IN AN ACUTE ANGLE TRIANGLE ABC , sec A( 1+ sec A) secB(1+secB) sec C (1+sec C ) =?
J K SEN , 7 Years ago
Grade 12th pass
Trigonometry> IN AN ACUTE ANGLE TRIANGLE ABC , sec A( 1...
1 Answers
Saurabh Koranglekar
Last Activity: 5 Years ago
Dear student
As there is no condition consider equilateral triangle
Sec A = 2 = Sec B= Sec C
Ans is (2*3)*(2*3)*(2*3) = 216
Regards
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