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In ∆ABC Prve that (b) partr1.r2 + r2.r3 + r3.r1 = s^2

In ∆ABC Prve that (b) partr1.r2 + r2.r3 + r3.r1 = s^2

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Grade:11

1 Answers

Arun
25757 Points
5 years ago
As we know
r = \LARGE \Delta/s
r1 = \LARGE \Delta/s-a
r2 = \LARGE \Delta/s-b
r3= \LARGE \Delta/s-c
Put these value in LHS
We get
\LARGE \Delta^2[1/(s-b)*(s-a)  +1/(s-b)(s-c)  +1/ (s-c)(s-a)]
Solve thia and you will get s2

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