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Grade: 11
        In 🔺 ABC,  2ca.sin(A-B+C)/2 is equal to... (a) a²+b²-c²                      (b) c²+a²-b²(c) b²-c²-a²                        (D) c²-a²-b²
11 months ago

Answers : (1)

Arun
15941 Points
							
A+B+C=Pi

so A+C = Pi - B

so here it will be :  2ac.sin(Pi/2 -B) = 2ac.cosB

by cosine rule, we have: c2+a2-b2 = 2ac cos B

option B
11 months ago
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