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In a triangle,prove that sin 3A sin(B-C)+sin 3Bsin(C-A)+sin3C(A-B)=0

In a triangle,prove that sin 3A sin(B-C)+sin 3Bsin(C-A)+sin3C(A-B)=0

Grade:12th pass

2 Answers

Saurabh Koranglekar
askIITians Faculty 10336 Points
2 years ago
Vikas TU
14149 Points
2 years ago
Dear student 
Dear student
Please approach using
( Sin A/ a) = ( sin B / b ) = ( sin C / c) = k
Expand sin 3A = 3ak - 4 ( ak)^3
If doubt still persists kindly revert for complete solution
Regards

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