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question mark

In a triangle ABC the value of acosA+bcosB+cCosC/a+b+c is equal to
(A) r/R
(b)R/2r
(C)R/r
(D)2r/R

PRAMAY , 11 Years ago
Grade 11
anser 1 Answers
Yash Baheti
Hi,

Follow the steps to reach the answer :

Apply the cos formula in terms of S, a, b, c.
Now rearrange the three terms and apply the formula which will connect R & r to S, a, b, c.

You will get the answer.
Last Activity: 11 Years ago
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