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In a triangle ABC the value of acosA+bcosB+cCosC/a+b+c is equal to (A) r/R (b)R/2r (C)R/r (D)2r/R

In a triangle ABC the value of acosA+bcosB+cCosC/a+b+c is equal to
 
(A) r/R
(b)R/2r
(C)R/r
(D)2r/R

Grade:11

1 Answers

Yash Baheti IIT Roorkee
askIITians Faculty 97 Points
9 years ago
Hi,

Follow the steps to reach the answer :

Apply the cos formula in terms of S, a, b, c.
Now rearrange the three terms and apply the formula which will connect R & r to S, a, b, c.

You will get the answer.

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