In a triangle ABC, if cos A / a = cos B / b = cos C / c and the side a = 2, then area of the triangle is
Samir Madan
12 Years agoGrade 12
1 Answer
bharat bajaj
12 Years ago
cos A / a = cos B / b = cos C / c cos A / (2R sin A) = cos B / (2R sin B) = cos C / (2R sin C) cot A = cot B = cot C A = B = C ?ABC is equilateral. Area == THanks