In a triangle ABC , Cot (A/2) Cot(B/2)= a+b+c /a+b-c
In a triangle ABC , Cot (A/2) Cot(B/2)= a+b+c /a+b-c
Samaira Shah , 8 Years ago
Grade 11
Trigonometry> In a triangle ABC , Cot (A/2) Cot(B/2)= a...
1 AnswersSaurabh Koranglekar
Dear student
Please find the link below
https://www.askiitians.com/forums/Trigonometry/in-abc-show-that-tan-a-2-tanb-2-a-b-c-a-b-ci-ve_190461.htm
Regards
Please find the link below
https://www.askiitians.com/forums/Trigonometry/in-abc-show-that-tan-a-2-tanb-2-a-b-c-a-b-ci-ve_190461.htm
Regards
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