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In a triangle ABC , Cot (A/2) Cot(B/2)= a+b+c /a+b-c

In a triangle ABC , Cot (A/2) Cot(B/2)= a+b+c /a+b-c

Grade:11

1 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
3 years ago

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