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in a triangle ABC, cos A=sin B/sin C +sin C/ sin B -sin 2 A/sin B.sin C

in a triangle ABC, cos A=sin B/sin C +sin C/ sin B -sin2A/sin B.sin C

Grade:11

1 Answers

Deepak Kumar Shringi
askIITians Faculty 4407 Points
4 years ago
This is not clear repost it

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