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in a triangle ABC, AD i the altitude from A givven b>c, angle C =2 degree and AD= (abc)/(b^2-c^2) find angle b

in a triangle ABC, AD i the altitude from A givven b>c, angle C =2 degree and AD= (abc)/(b^2-c^2)  find angle b

Grade:11

1 Answers

Arun
25750 Points
6 years ago
 

AD=c sinB=abc/(b² - c²)

 

             or sinB=ab/(b² - c²)

 

              or sinB=sinA sinB/sin(B+C) sin(B-C)

 

                or sinB=sinAsinB/sinAsin(B-C)

 

                or sin(B-C)=1=sin90°

 

                     or B-C=90°

but C = 2

so angle B = 92 degree

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