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In a triangle ABC, A=2 pii/3, b-c=3.3^1/2 cm and area of triangle ABC =9.3^1/2/2 cm^2.Then a is (A) 6.3^1/2 cm (B)9 cm (C)18cm (D)none of these

In a triangle ABC, A=2 pii/3, b-c=3.3^1/2 cm and area of triangle ABC =9.3^1/2/2 cm^2.Then a is
(A) 6.3^1/2 cm
(B)9 cm
(C)18cm
(D)none of these 

Grade:11

1 Answers

Ravi
askIITians Faculty 69 Points
6 years ago
We have an angle A
The difference of 2 sides: b-c which can be used to frame an equality by squaring it
So the formulae that need to be used are:
Area of triangle: ½ bc Sin A
a2= b2 + c2-2bcCosA (COsine law of triangle)
a/SinA= b/SinB=c/SinC (Sin law of triangle)

Use these formulae to get the answer...

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