In a right angled triangle the hypotenuseis four times as long as the perpendicular drawn to it from the opposite vertex. One of the acute angle isa)15°b)30°c)45° d) none of these

Sorry but I didn`t get the language plz explain it in english And explain it step by step............... ...............

So let the triangle of sides ab, bc and ac, where ac is the hypotenuse of side 4x and the opposite perpendicular side ab is x . Let the angle you needs to find is y. Sin(y) = opposite / hypotenuse = x / 4x = 1/4 ............ y = sin^-1 ( 1/4 ) which is approximately equal to 75 and 15 . Since, it`s an acuteness angle the answer is 15

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