Grade 12Trigonometry
In a ?ABC, ?C = p / 2, then 2 (r + R) is equal to
2 Answers
bharat bajaj
?C = p / 2
R = c / (2 sin C) = c / 2
Now, 2 (r + R) = 2 r + 2 R
= 2 (s - c)tan(C / 2) + 2 (c / 2)
= 2s - 2c + c
= 2s - c
= a + b
Thanks
R = c / (2 sin C) = c / 2
Now, 2 (r + R) = 2 r + 2 R
= 2 (s - c)tan(C / 2) + 2 (c / 2)
= 2s - 2c + c
= 2s - c
= a + b
Thanks
Bharat Bajaj
IIT Delhi
IIT Delhi
askiitians faculty
bharat bajaj
?C = p / 2
R = c / (2 sin C) = c / 2
Now, 2 (r + R) = 2 r + 2 R
= 2 (s - c)tan(C / 2) + 2 (c / 2)
= 2s - 2c + c
= 2s - c
= a + b
Thanks
R = c / (2 sin C) = c / 2
Now, 2 (r + R) = 2 r + 2 R
= 2 (s - c)tan(C / 2) + 2 (c / 2)
= 2s - 2c + c
= 2s - c
= a + b
Thanks
Bharat Bajaj
IIT Delhi
IIT Delhi
askiitians faculty
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