Ajay Verma
Last Activity: 11 Years ago
soln:
cosx+sinx= 1/2
square both sides..
(cosx+sinx)^2 = 1/4
1+ 2*sinx*cosx = 1/4
sin 2x = -3/4
2 tan x/(1+tan2x) = -3/4
-8 tan x = 3(1+tan2x)
3 tan2x + 8 tan x + 3 = 0
solving this
tan x = {-8 + 2(7)1/2}/ 6 & {-8 - 2(7)1/2}/ 6
Thanks and Regards,
Ajay verma,
askIITians faculty,
IIT HYDERABAD