Grade 11Trigonometry
(*)If x =a (sec theta + tan theta) square, y = b (sec theta – tan theta) square then x square.y square =
(*)
If x =a (sec theta + tan theta) square, y = b (sec theta – tan theta) square then x square.y square =
1 Answer
Nishant Vora
Hello student, Please find the answer to your question below
x =a (sec theta + tan theta)2
y = b (sec theta – tan theta)2
x*y =a (sec theta + tan theta)2 * b (sec theta – tan theta)2
= ab (sec2 theta – tan 2theta)2
= ab [because sec2 theta – tan 2theta = 1]
therefore x2 * y2 = 1
x =a (sec theta + tan theta)2
y = b (sec theta – tan theta)2
x*y =a (sec theta + tan theta)2 * b (sec theta – tan theta)2
= ab (sec2 theta – tan 2theta)2
= ab [because sec2 theta – tan 2theta = 1]
therefore x2 * y2 = 1
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