If theta is acute and (1-a square) sin theta = (1+a square) cos theta, then sin theta =

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Nishant Vora · Answer

Hello student, Please find the answer to your question below

(1-a²) sinØ = (1+a ²) cos Ø
tanØ = (1+a²)/(1-a²)

So , sinØ = (1+a²)/ root{(1+a²)²+(1-a²)²}

Now simplify the above

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If theta is acute and (1-a square) sin theta = (1+a square) cos theta, then sin theta =

If theta is acute and (1-a square) sin theta = (1+a square) cos theta, then sin theta =

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