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if tan( pie/4 + theta) + tan (pie/4 – theta)= a then tan cube (pie/4 + theta) + tan cube(pie/4-theta) =

Hello student, Please find the answer to your question below

tan( pie/4 + theta) + tan (pie/4 – theta)= a
(1+tanØ)/(1- tanØ) + (1-tanØ)/(1+tanØ) = a
=> a = 4tanØ/ (1 – tan²Ø)
From here you can find out tanØ
once you get tanØ ….you can get tan( pie/4 + theta) and tan (pie/4 – theta)

Then put in the required equation