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If tanα = m/(m+1), tanβ = 1/ (2m+1), the α+β is equal to : π/4 π/3 tan^-1[m/(2m+1)] tan^-1[(m+1)/(2m+1)]

If tanα =  m/(m+1), tanβ = 1/ (2m+1), the α+β is equal to :
  1. π/4
  2. π/3
  3. tan^-1[m/(2m+1)]
  4. tan^-1[(m+1)/(2m+1)]
 
 

Grade:11

1 Answers

Harshit Singh
askIITians Faculty 5963 Points
3 years ago
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