if tan(a- b)=1 and sec(a+b)=2/root 3 . find the smallest positive values of a and b and also their most general values
Arpita
12 Years agoGrade
2 Answers
Sher Mohammad
12 Years ago
a-b=nPi+ Pi/4 1/cos(a+b)=sec(a+b)=2/root 3 cos(a+b)=root 3/2 a+b=2nPi+Pi/6 a=2nPi+1/2(Pi/4+Pi/6) b=2nPi+1/2(Pi/6-Pi/4) for n=0, smallest value of a=1/2(Pi/4+Pi/6) smallest value of b=1/2(Pi/6-Pi/4)
sher mohammad b.tech, iit delhi
Santosh kumar Anakapalli
9 Years ago
tan(A-B) = 1 then A-B = 45 or 225 degrees
Sec(A+B) = 2/sqt3 then A+B either 30 or 330 degrees
then if take A-B = 45 and A+B = 330 then A= 187.5 degrees, B = 142.5 degrees.