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if tan(a- b)=1 and sec(a+b)=2/root 3 . find the smallest positive values of a and b and also their most general values if tan(a- b)=1 and sec(a+b)=2/root 3 . find the smallest positive values of a and b and also their most general values
a-b=nPi+ Pi/41/cos(a+b)=sec(a+b)=2/root 3cos(a+b)=root 3/2a+b=2nPi+Pi/6a=2nPi+1/2(Pi/4+Pi/6)b=2nPi+1/2(Pi/6-Pi/4)for n=0,smallest value of a=1/2(Pi/4+Pi/6)smallest value of b=1/2(Pi/6-Pi/4)sher mohammadb.tech, iit delhi
tan(A-B) = 1 then A-B = 45 or 225 degreesSec(A+B) = 2/sqt3 then A+B either 30 or 330 degreesthen if take A-B = 45 and A+B = 330 then A= 187.5 degrees, B = 142.5 degrees. Santosh Kumar AnakapalliNIT Trichy
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