If tan a= 2k - x÷k√3 and tan b= x√3 ÷ 2k -x then prove that (a-b)=30°.

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Arun · Answer

Dear student Use tan(a-b) = tan A - tanB/(1+tanA tanB) Put tanA and tanB You will get tan(a-b) = 1/sqrt(3) Hence a - b = 30° Regards Arun (askIITians forum expert)

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If tan a= 2k - x÷k√3 and tan b= x√3 ÷ 2k -x then prove that (a-b)=30°.

If tan a= 2k - x÷k√3 and tan b= x√3 ÷ 2k -x then prove that (a-b)=30°.

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If tan a= 2k - x÷k√3 and tan b= x√3 ÷ 2k -x then prove that (a-b)=30°.

If tan a= 2k - x÷k√3 and tan b= x√3 ÷ 2k -x then prove that (a-b)=30°.

1 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Trigonometry

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