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If tan a= 2k - x÷k√3 and tan b= x√3 ÷ 2k -x then prove that (a-b)=30°.

If tan a= 2k - x÷k√3 and tan b= x√3 ÷ 2k -x then prove that (a-b)=30°.

Grade:11

1 Answers

Arun
25763 Points
3 years ago
Dear student
 
Use 
tan(a-b) = tan A - tanB/(1+tanA tanB)
Put tanA and tanB
 
You will get
tan(a-b) = 1/sqrt(3)
Hence
a - b = 30°
 
Regards
Arun (askIITians forum expert)

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