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tanA = 1/3, tanB = 1/7
Then tan(2A) = 2tanA/(1-tan^2A) = (2/3)/(1 - 1/9) = 3/4
tan(2A + B) = (tan2A + tanB)/(1 - tan2A.tanB)
tan(2A + b) = (3/4 + 1/7)/(1 - (3/4)(1/7))
tan(2A + B) = (21/28 + 4/28)/(1 - 3/28)
tan(2A + B) = (25/28)/(25/28) = 1
i.e. 2A + B = 45°
Regards
Arun (askIITians forum expert)
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