Vikas TUApproved Tutor Answer10 Years agoFrom eqn. tan2A=1+2tan2Bsin^2A/cos^2A = 1 +2sin^2B/cos^2B=> sin^2A*cos^2B/cos^2A = cos^2B +2sin^2B=> sin^2A*cos^2B = (cos^2B +2sin^2B)*cos^2A=> sin^2A -sin^2Asin^2B = (1 -sin^2A)(1 + sin^2B) = 1 -sin^2A + sin^2B -sin^2Asin^2B=> 2sin2A=1+sin2B H.proved