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If sinAsinB -cosAcosB = 1 show that tanA+tanB=0
multiply given given equation by -1we get cos(A+B)= (-1) it means that A+B = pinow tanA+tanB =0 we have to prove it sinA/cosA+sinB/cosB= 0 TAKING LCM . we get sin(A+B)=0 it means we had to prove that sin(A+B)=0and we have alredy concluded that A+B=pi so sin(pi) = 0 approve if useful
use the identity coa(a+b)then you will get that a+b = piea= pie-bsubstitute this value in the tan term and you will get the answer
approve if useful
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