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If sina+sinb+sinc=3 then find the value of cosa+cosb+cosc
Hiithe maximum value for sin is 1 and since you have three sin's adding up to 3, each of the sin's must be 1!So A = B = C = 90 degrees or any angle coterminal with 90 degrees.And the cos of 90 degrees is zero. So cos(A)+cos(B)+cos(C) = 0+0+0 = 0.
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