If sinA+sin^2A=1 and acos^12A+bcos^8A+ccos^6A−1=0 then b+c/a+b=?

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Arun · Answer

sin@+sin^2@=1 =>sin@=1-sin^2@=cos^2@ Now we know cos^12@+3cos^10@+3cos^8@+cos^6@-1 = 0 Hence Now find a, b, c, d and then find answer.

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If sinA+sin^2A=1 and acos^12A+bcos^8A+ccos^6A−1=0 then b+c/a+b=?

If sinA+sin^2A=1 and acos^12A+bcos^8A+ccos^6A−1=0 then b+c/a+b=?

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If sinA+sin^2A=1 and acos^12A+bcos^8A+ccos^6A−1=0 then b+c/a+b=?

If sinA+sin^2A=1 and acos^12A+bcos^8A+ccos^6A−1=0 then b+c/a+b=?

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