If sinA=1/3, sinB=1/4 find sin(A+B), where A and B are acute

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Arun · Answer

As we know If sinA = 1/3 Then cos A = 8/3 Now If sinB = ¼ Then cos B = 15/4 Hence Sin(A+B) = sinA cosB + cos A sinB Now put the values Sin(A+B) = 15/12 + 8/12

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If sinA=1/3, sinB=1/4 find sin(A+B), where A and B are acute

If sinA=1/3, sinB=1/4 find sin(A+B), where A and B are acute

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