Grade 12th passTrigonometryif sin(x)=nsin(x+2a) then find the value oftan(x+a) Sridhar Havish Jallepalli 10 Years agoGrade 12th pass
Himanshu10 Years ago sin(x+2a) / sin(x) = 1/n [sin(x+2a) + sin(x)] / [sin(x+2a) – sin(x)] = (1+n) / (1-n)(:.Using componendo and dividendo) 2.sin(x+a).cos(a) / 2.sin(a).cos(x+a) = (1+n) / (1-n) tan(x+a) / tan(a) = (1+n) / (1-n) tan(x+a) = (1+n) × tan(a)/ (1-n)The above is the required answer.