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If sin B = sin (2A + B) /5 , then 2tan (A + B) / tan A =
If sin B = sin (2A + B) /5 , then 2tan (A + B) / tan A =

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2 years ago

2074 Points
```							write this as:sin (2A + B)/sin B = 5/1apply componendo and dividendo[sin (2A + B)+sin B]/[sin (2A + B) – sin B]= (5+1)/(5 – 1)now apply sin x + sin y = 2 sin (x+y)/2 *cos (x−y)/2 and sin x – sin y = 2 sin (x-y)/2 *cos (x+y)/2 2sin(A+B)cosA/2sinAcos(A+B)=6/4=3/2tan(A+B)/tanA=3/2or 2tan(A+B)/tanA = 3
```
2 years ago
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Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions