If sin-1 x + sin-1 y + sin-1 z =3π/2 then x^100+y^100+z^100-9/(x^101+y^101+z^101)= Options are. a)0 b)1 c)2 d)3

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Arun · Answer

Dear student Sin -1 x + sin -1 y + sin -1 z = 3 /2 Means x = y = z = 1 Hence Expression becomes (1+1+1 -9)/(1+1+1) = -6/3 = -2 Regards Arun (askIITians forum expert)

Kushagra Madhukar · Answer

Dear student, Please find the answer to your question. Sin -1 x + sin -1 y + sin -1 z = 3 /2 Means x = y = z = 1 Hence Expression becomes (1+1+1 -9)/(1+1+1) = -6/3 = -2 Thanks and regards, Kushagra

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If sin-1 x + sin-1 y + sin-1 z =3π/2 then x^100+y^100+z^100-9/(x^101+y^101+z^101)= Options are. a)0 b)1 c)2 d)3

If sin-1 x + sin-1 y + sin-1 z =3π/2 then x^100+y^100+z^100-9/(x^101+y^101+z^101)= Options are. a)0 b)1 c)2 d)3

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If sin-1 x + sin-1 y + sin-1 z =3π/2 then x^100+y^100+z^100-9/(x^101+y^101+z^101)= Options are. a)0 b)1 c)2 d)3

If sin-1 x + sin-1 y + sin-1 z =3π/2 then x^100+y^100+z^100-9/(x^101+y^101+z^101)= Options are. a)0 b)1 c)2 d)3

2 Answers

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