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# If sin​-1 x + sin​​-1 y = π/2,  then ​x​2 is equal to                                                      1) y​2                  2)(1-y)​1/2            3) 1 – y​2     4) 0

Shahid
74 Points
3 years ago
Dear Tushar ,
We Know that
Sin-1x + cos-1x = $\dpi{80} \Pi$/2
And Given is that Sin-1x + Sin-1y = $\dpi{80} \Pi$/2

Therefore , we get that...
Sin-1y = cos-1x
Sin-1y = Sin-1($\dpi{80} \sqrt{1 - x^{2}}$

Therefore
y = $\dpi{80} \sqrt{1 - x^{2}}$

On Squaring both sides .
we get

x​2  = 1 – y​2
ankit singh
9 months ago
his problem involves both differentiation as well as inverse trigonometric functions.

Now given that,

sin1x+sin1y=π2

sin1x=π2sin1y

sin1x=cos1y

y=cossin1x

dydx=sinsin1x.ddx(sin1x)

dydx=x11x2

dydx=x1x2.