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Trigonometry> if [sin -1 x]>[cos -1 x] then x belongs t...

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if [sin^-1x]>[cos^-1x] then x belongs to interval
[tan sin cos 1,tan sin cos sin 1].prove

Dimple Gahlot , 11 Years ago

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1 Answers

Arun Kumar

Hello Student

You should do this by graph.
From what i understand by your representation.

$\\ \left \lfloor sin^{-1}x\right \rfloor= -2,-1,0,1 \\ \\\left \lfloor cos^{-1}x \right \rfloor= 0,1,2,3 \\=>sin^{-1}x \in (1,\pi/2] => x \in (sin 1,1]=(0.84,1] \\and\,cos^{-1}x \in (0,1) => x \in (cos1,1)=(0.58,1) \\$taking common $(sin 1,1] \\\left \lfloor \, \right \rfloor$ means greatest integer function$$

Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty

Last Activity: 11 Years ago

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