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Grade 10Trigonometry

if secx+tanx=5, then find the value of (tanx+secx-1)/(tanx-secx+1)

Profile image of Seethalakshmi Koravangat
8 Years agoGrade 10
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1 Answer

Profile image of Hari Sundar Pyda
8 Years ago
secx+tanx=5(tanx+secx-1)/(tanx-secx+1)= (tanx+5-tanx-1) / (tanx+5-tanx+1)= 4 / 6= 2 / 3.Hope it helps!!