if sec∂ and cosec∂ are the roots of x 2 -px+q=0 then p 2 =q(q-2) p 2 +q 2 =2q p 2 =q(q+1) p 2 =q(q-1) p 2 =q(q+2) pls explain

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ASh · Answer

guys please answer................................................................................................................

amit kumar · Answer

Sum of roots seca+coseca=p.....1And product seca.coseca=q......2From 2 sina.cosa=1/qFrom 1 sina+cosa/sina.cosa=sina+cosa)q=pSquiringSin²a+cos²a+2sina.cosa=p²/q²So 1+2/q=p²/q²Which on simplification givesP²=q²+2q=q(q+2)Last choice

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if sec∂ and cosec∂ are the roots of x 2 -px+q=0 then p 2 =q(q-2) p 2 +q 2 =2q p 2 =q(q+1) p 2 =q(q-1) p 2 =q(q+2) pls explain

if sec∂ and cosec∂ are the roots of x²-px+q=0 then

p²=q(q-2)

p²+q²=2q

p²=q(q+1)

p²=q(q-1)

p²=q(q+2) pls explain

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if sec∂ and cosec∂ are the roots of x 2 -px+q=0 then p 2 =q(q-2) p 2 +q 2 =2q p 2 =q(q+1) p 2 =q(q-1) p 2 =q(q+2) pls explain

if sec∂ and cosec∂ are the roots of x2-px+q=0 then p2=q(q-2) p2+q2=2q p2=q(q+1) p2=q(q-1) p2=q(q+2) pls explain

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if sec∂ and cosec∂ are the roots of x²-px+q=0 then

p²=q(q-2)

p²+q²=2q

p²=q(q+1)

p²=q(q-1)

p²=q(q+2) pls explain