if sec∂ and cosec∂ are the roots of x2-px+q=0 then - p2=q(q-2)
- p2+q2=2q
- p2=q(q+1)
- p2=q(q-1)
- p2=q(q+2) pls explain
if sec∂ and cosec∂ are the roots of x2-px+q=0 then
- p2=q(q-2)
- p2+q2=2q
- p2=q(q+1)
- p2=q(q-1)
- p2=q(q+2) pls explain

Last Activity: 3 Years ago

Last Activity: 3 Years ago

Last Activity: 3 Years ago

Last Activity: 3 Years ago

Last Activity: 3 Years ago