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If M and m denote maximum and minimum value of (49cos 2 X +sin 2 x) 1/2 + (49sin 2 x+cos 2 x) 1/2 then find the value of (M+m). Thanks in advance.please solve it fast.
If M and m denote maximum and minimum value of (49cos2X +sin2x)1/2 + (49sin2x+cos2x)1/2 then find the value of (M+m).     Thanks in advance.please solve it fast.

```
2 years ago

54 Points
```							In this question we use a easy trigonometric property:sin2x+cos2x=1And, then we use the maximum and minimum values possible for cos2x which are 1(one) and 0(zero) respectively.M-maximum valueM=max{[48cos2x +(cos2x+sin2x)]1/2} M=max{[48cos2x + 1]1/2} maxmimum value of cos2x is 1M=(48(1) + 1)½ M=(49)½ M=7m-minimum valuem=min{[48cos2x +(cos2x+sin2x)]1/2} m=min{[48cos2x + 1]1/2} minimum value of cos2x is 0m=(48(0)+1)1/2 m=1 The value of M+m is 8.
```
2 years ago
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• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions