Snehal Jadhav
Last Activity: 6 Years ago
In this question we use a easy trigonometric property:
sin2x+cos2x=1
And, then we use the maximum and minimum values possible for cos2x which are 1(one) and 0(zero) respectively.
M-maximum value
M=max{[48cos2x +(cos2x+sin2x)]1/2}
M=max{[48cos2x + 1]1/2}
maxmimum value of cos2x is 1
M=(48(1) + 1)½
M=(49)½
M=7
m-minimum value
m=min{[48cos2x +(cos2x+sin2x)]1/2}
m=min{[48cos2x + 1]1/2}
minimum value of cos2x is 0
m=(48(0)+1)1/2
m=1
The value of M+m is 8.
