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If in a ∆ABC, angle B = 60°, angle C= 45°, D is a point on segment BC such that DC= 3BD, then sin angle BAD/sin angle CAD= 1/√k, then k is?

If in a ∆ABC, angle B = 60°, angle C= 45°, D is a point on segment BC such that DC= 3BD, then sin angle BAD/sin angle CAD= 1/√k, then k is?

Grade:11

1 Answers

Deepak Kumar Shringi
askIITians Faculty 4405 Points
3 years ago
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